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(F)=-F^2-14F-47
We move all terms to the left:
(F)-(-F^2-14F-47)=0
We get rid of parentheses
F^2+14F+F+47=0
We add all the numbers together, and all the variables
F^2+15F+47=0
a = 1; b = 15; c = +47;
Δ = b2-4ac
Δ = 152-4·1·47
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{37}}{2*1}=\frac{-15-\sqrt{37}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{37}}{2*1}=\frac{-15+\sqrt{37}}{2} $
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